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6v^2-8v-30=0
a = 6; b = -8; c = -30;
Δ = b2-4ac
Δ = -82-4·6·(-30)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-28}{2*6}=\frac{-20}{12} =-1+2/3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+28}{2*6}=\frac{36}{12} =3 $
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